Find the equation of the line using the point-slope formula. Write the final equation using the slope-intercept form. the $x$-intercept is 1 , and $(x,y)=(-2,3)$ is a point on the line

Step 1 ：We are given that the line passes through the point (-2,3) and has an x-intercept of 1. This means the line also passes through the point (1,0).

Step 2 ：We can find the slope of the line using the formula $m=\frac{y_2-y_1}{x_2-x_1}$. Substituting the given points into this formula, we get $m=\frac{0-3}{1-(-2)}=-1.0$.

Step 3 ：Next, we use the point-slope form of the line equation, which is $y-y_1=m(x-x_1)$. Substituting the point (-2,3) and the slope -1.0 into this formula, we get $y-3=-1.0(x-(-2))$.

Step 4 ：Solving this equation for y, we get $y=-1.0x+1.0$.

Step 5 ：Finally, we can write the equation of the line in slope-intercept form, which is $y=mx+b$. Substituting the slope -1.0 and the y-intercept 1.0 into this formula, we get $y=-1.0x+1.0$.

Step 6 ：$\boxed{{\displaystyle y=-x+1}}$ is the equation of the line.