Determine whether the complex number is a solution of the equation.
$$5-i;x^2-10x+26=0$$
Is $5-i$ a solution of the equation $x^2-10x+26=0$ ?
Yes
No

Step 1 ：To determine if a complex number is a solution to the equation, we can substitute the complex number into the equation and see if the equation holds true. If it does, then the complex number is a solution to the equation. If it doesn't, then it is not a solution.

Step 2 ：In this case, we need to substitute $5-i$ into the equation $x^2-10x+26=0$ and see if the left side equals to the right side.

Step 3 ：Substitute $x=5-i$ into the equation, we get $(-24+(5-i{)}^2+10\ast i$.

Step 4 ：The result of substituting $5-i$ into the equation is not zero, which means that $5-i$ is not a solution to the equation $x^2-10x+26=0$.

Step 5 ：$\boxed{{\displaystyle \text{No, }5-i\text{ is not a solution of the equation }{x}^2-10x+26=0}}$