Problem

5
2
nd understand (R\&U): Stewart's pp 95-113
The given limit is a derivative of a function f(x) at point a. Find the expression that represents the function and the value of a.
limh01(1+h)27h
Note: Due to the choice of the formula for the derivative, the limits do not depend on the value of m. Hence the limit for the functions f(x) and f(x+m), where m is any real number, are the same in this case. Give the answer for m=0.
f(x)=+C,C=Ra=1 Clear all 
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Answer

a=1

Steps

Step 1 :The given limit is the definition of the derivative of a function at a point.

Step 2 :The function is f(x)=x27 and the point is a=1.

Step 3 :The derivative of f(x) is f(x)=27x26, so the limit is equivalent to f(1)=27126=27.

Step 4 :The expression that represents the function is f(x)=x27+C, where C is any real number, and the value of a is 1.

Step 5 :f(x)=x27+C,C=R

Step 6 :a=1

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