Problem

(c) Find dydx where x+y+xy=1.

Answer

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Answer

dydx=2xyy2xy+x

Steps

Step 1 :Understand the problem: We are asked to find the derivative of y with respect to x, given the equation x+y+xy=1.

Step 2 :Differentiate both sides of the equation with respect to x: 1+dydx+121xy(y+xdydx)=0.

Step 3 :Simplify the equation by multiplying through by 2xy to clear the fraction: 2xy+2xydydx+y+xdydx=0.

Step 4 :Collect terms involving dydx: (2xy+x)dydx=2xyy.

Step 5 :Solve for dydx: dydx=2xyy2xy+x.

Step 6 :Check the result by substituting dydx back into the differentiated equation to check if it satisfies the equation. If it does, then the result is correct.

Step 7 :dydx=2xyy2xy+x

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