Use the functions $f(x)=x^{2}-3 x-18$ and $g(x)=x^{2}+3 x-18$ to answer parts (a) through $(g)$.
(a) Solve $f(x)=0$.
(d) Solve $f(x)> 0$.
(g) Solve $f(x) \geq 1$.
(b) Solve $g(x)=0$.
(e) Solve $g(x) \leq 0$.
(c) Solve $f(x)=g(x)$.
(f) Solve $f(x)> g(x)$.
(a) The solution set is $\{-3,6\}$.
(Use a comma to separate answers as needed.)
(b) The solution set is
(Use a comma to separate answers as needed.)
Clear all
Check answer
Answer
Final Answer: The solution set is \(\boxed{-3, 6}\).
Step 1 ：The first question asks to solve the equation \(f(x)=0\). This is a quadratic equation and can be solved using the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), where \(a\), \(b\), and \(c\) are the coefficients of the quadratic equation \(ax^2 + bx + c = 0\). In this case, \(a=1\), \(b=-3\), and \(c=-18\).
Step 2 ：The solutions to the equation \(f(x)=0\) are \(x=-3\) and \(x=6\). These are the x-values where the function \(f(x)\) intersects the x-axis.
Step 3 ：Final Answer: The solution set is \(\boxed{-3, 6}\).
