Problem

Express f(x) in the form f(x)=(xk)q(x)+r for the given value of k.
f(x)=5x3+x2+x7,k=1

Answer

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Answer

f(x)=(x+1)(5x24x+1)8 is the final expression of the polynomial f(x) in the form f(x)=(xk)q(x)+r.

Steps

Step 1 :We are given the polynomial function f(x)=5x3+x2+x7 and the value k=1.

Step 2 :We are asked to express the polynomial f(x) in the form f(x)=(xk)q(x)+r, which is equivalent to dividing the polynomial f(x) by the binomial (xk) and expressing the result as a quotient q(x) and a remainder r.

Step 3 :In this case, we are dividing the polynomial f(x) by the binomial (x+1), since k=1.

Step 4 :The quotient q(x) and the remainder r obtained from the division of f(x) by (x+1) are given by q(x)=5x24x+1 and r=8.

Step 5 :f(x)=(x+1)(5x24x+1)8 is the final expression of the polynomial f(x) in the form f(x)=(xk)q(x)+r.

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