Type the slope-intercept equation of the line that passes through the points $(2,-2)$ and $(3,2)$.
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Step 1 ：The slope-intercept form of a line is given by \(y = mx + b\), where \(m\) is the slope of the line and \(b\) is the y-intercept.

Step 2 ：The slope of a line passing through two points \((x_1, y_1)\) and \((x_2, y_2)\) can be calculated using the formula \(m = \frac{y_2 - y_1}{x_2 - x_1}\).

Step 3 ：Substitute the given points into the formula: \(m = \frac{2 - (-2)}{3 - 2} = 4.0\).

Step 4 ：Once we have the slope, we can substitute one of the points into the equation to solve for \(b\).

Step 5 ：Substitute the point \((2,-2)\) and the slope into the equation: \(-2 = 4*2 + b\), solve for \(b\), we get \(b = -10.0\).

Step 6 ：Substitute \(m = 4.0\) and \(b = -10.0\) into the slope-intercept form, we get the final equation of the line: \(y = 4x - 10\).

Step 7 ：\(\boxed{y = 4x - 10}\) is the slope-intercept equation of the line that passes through the points \((2,-2)\) and \((3,2)\).