Type the slope-intercept equation of the line that passes through the points $(2,-2)$ and $(3,2)$.
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Step 1 ：The slope-intercept form of a line is given by $y=mx+b$, where $m$ is the slope of the line and $b$ is the y-intercept.

Step 2 ：The slope of a line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ can be calculated using the formula $m=\frac{y_2-y_1}{x_2-x_1}$.

Step 3 ：Substitute the given points into the formula: $m=\frac{2-(-2)}{3-2}=4.0$.

Step 4 ：Once we have the slope, we can substitute one of the points into the equation to solve for $b$.

Step 5 ：Substitute the point $(2,-2)$ and the slope into the equation: $-2=4\ast 2+b$, solve for $b$, we get $b=-10.0$.

Step 6 ：Substitute $m=4.0$ and $b=-10.0$ into the slope-intercept form, we get the final equation of the line: $y=4x-10$.

Step 7 ：$\boxed{{\displaystyle y=4x-10}}$ is the slope-intercept equation of the line that passes through the points $(2,-2)$ and $(3,2)$.