Hallar el $9 .^{\circ}$ término de la sucesión geométrica cuya razón común es $\frac{1}{3}$ y cuyo primer término es 2 .

Step 1 ：The problem is asking for the 9th term of a geometric sequence where the common ratio is \(\frac{1}{3}\) and the first term is 2.

Step 2 ：In a geometric sequence, the nth term can be found using the formula: \(a_n = a_1 * r^{(n-1)}\) where \(a_n\) is the nth term, \(a_1\) is the first term, r is the common ratio, and n is the term number.

Step 3 ：To find the 9th term, we can substitute \(a_1 = 2\), \(r = \frac{1}{3}\), and \(n = 9\) into the formula.

Step 4 ：Substituting the values into the formula, we get \(a_n = 2 * (\frac{1}{3})^{(9-1)}\)

Step 5 ：Solving the equation, we find that the 9th term of the geometric sequence is \(\boxed{0.000304831580551745}\)