Hallar el 9 .^{circ} término de la sucesión geométrica cuya razón común es frac{1}{3} y cuyo primer término es 2 .

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Accepted Answer

Step:1 ：The problem is asking for the 9th term of a geometric sequence where the common ratio is (frac{1}{3}) and the first term is 2.Step:2 ：In a geometric sequence, the nth term can be found using the formula: (a_n = a_1 * r^{(n-1)}) where (a_n) is the nth term, (a_1) is the first term, r is the common ratio, and n is the term number.Step:3 ：To find the 9th term, we can substitute (a_1 = 2), (r = frac{1}{3}), and (n = 9) into the formula.Step:4 ：Substituting the values into the formula, we get (a_n = 2 * (frac{1}{3})^{(9-1)})Step:5 ：Solving the equation, we find that the 9th term of the geometric sequence is (boxed{0.000304831580551745})

Answer

Step: 1 ：The problem is asking for the 9th term of a geometric sequence where the common ratio is (frac{1}{3}) and the first term is 2.Step: 2 ：In a geometric sequence, the nth term can be found using the formula: (a_n = a_1 * r^{(n-1)}) where (a_n) is the nth term, (a_1) is the first term, r is the common ratio, and n is the term number.Step: 3 ：To find the 9th term, we can substitute (a_1 = 2), (r = frac{1}{3}), and (n = 9) into the formula.Step: 4 ：Substituting the values into the formula, we get (a_n = 2 * (frac{1}{3})^{(9-1)})Step: 5 ：Solving the equation, we find that the 9th term of the geometric sequence is (boxed{0.000304831580551745})

Hallar el $9 .^{\circ}$ término de la sucesión geométrica cuya razón común es $\frac{1}{3}$ y cuyo primer término es 2 .

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Hallar el 9.∘ término de la sucesión geométrica cuya razón común es 13 y cuyo primer término es 2 .

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Hallar el $9 .^{\circ}$ término de la sucesión geométrica cuya razón común es $\frac{1}{3}$ y cuyo primer término es 2 .