Suppose you walk to your friend's house in $15 \mathrm{~min}$, then to the store which takes $45 \mathrm{~min}$, and then to school which takes $25 \mathrm{~min}$. If the distances are $A=476 \mathrm{~m}, \mathrm{~B}=680 \mathrm{~m}$, and $\mathrm{C}=794 \mathrm{~m}$ what was 50 ur average speed in kilometers per hour?

Step 1 ：Let's denote the distances to your friend's house, the store, and the school as \(A=476\) m, \(B=680\) m, and \(C=794\) m respectively.

Step 2 ：The time it takes to walk to each of these places is \(15\) minutes, \(45\) minutes, and \(25\) minutes respectively.

Step 3 ：We first convert these distances from meters to kilometers, and the time from minutes to hours. So, \(A=0.476\) km, \(B=0.68\) km, \(C=0.794\) km, and the times are \(0.25\) hours, \(0.75\) hours, and \(0.4166666666666667\) hours respectively.

Step 4 ：The total distance walked is the sum of the distances to each place, which is \(1.9500000000000002\) km.

Step 5 ：The total time spent walking is the sum of the time it takes to walk to each place, which is \(1.4166666666666667\) hours.

Step 6 ：The average speed is calculated by dividing the total distance by the total time. So, the average speed is approximately \(1.3764705882352941\) km/hr.

Step 7 ：Final Answer: The average speed is approximately \(\boxed{1.38 \mathrm{~km/hr}}\).