\[
f(x)=|x-3|
\]
\begin{tabular}{|c|c|}
\hline$x$ & $y$ \\
\hline-2 & \\
\hline-1 & \\
\hline 0 & \\
\hline 1 & \\
\hline 2 & \\
\hline
\end{tabular}

Step 1 ：The function given is \(f(x)=|x-3|\).

Step 2 ：The absolute value function \(|x|\) is defined as \(x\) if \(x \geq 0\) and \(-x\) if \(x < 0\). Therefore, \(|x-3|\) will be \(x-3\) if \(x-3 \geq 0\) (i.e., \(x \geq 3\)) and \(-(x-3)\) if \(x-3 < 0\) (i.e., \(x < 3\)).

Step 3 ：We are asked to find the values of the function at the points \(x=-2, -1, 0, 1, 2\).

Step 4 ：For \(x=-2\), since \(-2 < 3\), we use \(-(x-3)\) to get \(5\).

Step 5 ：For \(x=-1\), since \(-1 < 3\), we use \(-(x-3)\) to get \(4\).

Step 6 ：For \(x=0\), since \(0 < 3\), we use \(-(x-3)\) to get \(3\).

Step 7 ：For \(x=1\), since \(1 < 3\), we use \(-(x-3)\) to get \(2\).

Step 8 ：For \(x=2\), since \(2 < 3\), we use \(-(x-3)\) to get \(1\).

Step 9 ：So the values of the function \(f(x)=|x-3|\) at the points \(x=-2, -1, 0, 1, 2\) are \(5, 4, 3, 2, 1\) respectively.

Step 10 ：Thus, the completed table is: \[\begin{tabular}{|c|c|}\hline$x$ & $y$ \\ \hline-2 & 5 \\ \hline-1 & 4 \\ \hline 0 & 3 \\ \hline 1 & 2 \\ \hline 2 & 1 \\ \hline\end{tabular}\]

Step 11 ：\(\boxed{\text{Final Answer: The values of the function } f(x)=|x-3| \text{ at the points } x=-2, -1, 0, 1, 2 \text{ are } 5, 4, 3, 2, 1 \text{ respectively.}}\)