State the horizontal asymptote for the function $h(x)=-3^{x-1}+1$ :
$y=0$
$y=3$
$y=1$
$y=-1$
Final Answer: The horizontal asymptote for the function \(h(x)=-3^{x-1}+1\) is \(\boxed{y=1}\).
Step 1 :The horizontal asymptote of a function is the value that the function approaches as x approaches infinity or negative infinity.
Step 2 :For the function \(h(x)=-3^{x-1}+1\), as x approaches infinity, the term \(-3^{x-1}\) will approach negative infinity.
Step 3 :However, as x approaches negative infinity, the term \(-3^{x-1}\) will approach 0.
Step 4 :Therefore, the function will approach 1 from below as x approaches negative infinity.
Step 5 :Hence, the horizontal asymptote of the function is \(y=1\).
Step 6 :Final Answer: The horizontal asymptote for the function \(h(x)=-3^{x-1}+1\) is \(\boxed{y=1}\).