Problem

Measurement:
A dog kennel owner has $100 \mathrm{ft}$. of fencing to enclose a rectangular dog run. She wants it to be 5 times as long as it is wide. Find the dimensions of the dog run. What is the perimeter of the dog run?

Answer

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Answer

Final Answer: The dimensions of the dog run are \(\boxed{\frac{25}{3} \text{ ft}}\) wide and \(\boxed{\frac{125}{3} \text{ ft}}\) long.

Steps

Step 1 :Given that the total length of the fencing is 100 ft and the length of the dog run is 5 times its width, we can set up a system of equations to find the dimensions of the dog run.

Step 2 :Let's denote the width as \(w\) and the length as \(l\). We have two equations:

Step 3 :1. \(l = 5w\) (from the condition that the length is 5 times the width)

Step 4 :2. \(2*(l + w) = 100\) (from the condition that the total length of the fencing is 100 ft)

Step 5 :We can substitute the first equation into the second to solve for \(w\), and then use the value of \(w\) to find \(l\).

Step 6 :Substituting \(l = 5w\) into the second equation, we get \(2*(5w + w) = 100\), which simplifies to \(12w = 100\).

Step 7 :Solving for \(w\), we get \(w = \frac{25}{3}\).

Step 8 :Substituting \(w = \frac{25}{3}\) into the first equation, we get \(l = 5 * \frac{25}{3} = \frac{125}{3}\).

Step 9 :Final Answer: The dimensions of the dog run are \(\boxed{\frac{25}{3} \text{ ft}}\) wide and \(\boxed{\frac{125}{3} \text{ ft}}\) long.

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