A ball is dropped from a height of \( 44 \mathrm{~m} \). How much time (second unit) will pass before the ball hits the ground
5. Calculate t: \( t \approx 3.0063 \textrm{ s} \)
Step 1 :1. \( g = 9.81 \\mathrm{m/s^2} \)
Step 2 :2. \( h = 44 \mathrm{~m} \)
Step 3 :3. Use formula: \( t = \sqrt{\frac{2h}{g}} \)
Step 4 :4. Substitute given values: \( t = \sqrt{\frac{2(44)}{9.81}} \)
Step 5 :5. Calculate t: \( t \approx 3.0063 \textrm{ s} \)