What is the angle of refraction if a ray that makes an angle of ${25.0}^{\circ}$ with the normal in Air $(n = 1.00)$ travels to Flint Glass ( $n = 1.65$ )?
${0.256}^{\circ}$
${14.8}^{\circ}$
${0.697}^{\circ}$
${44.2}^{\circ}$

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Answer

Step 3: Substitute values and calculate: $θ_{2} = \arcsin \frac{1.00 \times \sin {25.0}^{\circ}}{1.65} = {14.8}^{\circ}$

Steps

Step 1 ：Step 1: Using Snell's Law: $n_{1} \sin θ_{1} = n_{2} \sin θ_{2}$

Step 2 ：Step 2: Solve for $θ_{2}$ : $θ_{2} = \arcsin \frac{n_{1} \sin θ_{1}}{n_{2}}$

Step 3 ：Step 3: Substitute values and calculate: $θ_{2} = \arcsin \frac{1.00 \times \sin {25.0}^{\circ}}{1.65} = {14.8}^{\circ}$