What is the angle of refraction if a ray that makes an angle of \( 25.0^{\circ} \) with the normal in Air \( (n=1.00) \) travels to Flint Glass ( \( n=1.65 \) )?
\( 0.256^{\circ} \)
\( 14.8^{\circ} \)
\( 0.697^{\circ} \)
\( 44.2^{\circ} \)

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Answer

Step 3: Substitute values and calculate: \( \theta_2 = \arcsin{\frac{1.00 \times \sin{25.0^{\circ}}}{1.65}} = 14.8^{\circ} \)

Steps

Step 1 ：Step 1: Using Snell's Law: \( n_1 \sin{\theta_1} = n_2 \sin{\theta_2} \)

Step 2 ：Step 2: Solve for \( \theta_2 \): \( \theta_2 = \arcsin{\frac{n_1 \sin{\theta_1}}{n_2}} \)

Step 3 ：Step 3: Substitute values and calculate: \( \theta_2 = \arcsin{\frac{1.00 \times \sin{25.0^{\circ}}}{1.65}} = 14.8^{\circ} \)