What is the angle of the $2^{nd}$ order bright fringe produced by two slits that are $8.25 \times 10^{- 5} m$ apart if the wavelength of the incident light is $4.50 \times 10^{- 7} m$ ?
${91.7}^{\circ}$
${1.60}^{\circ}$
${0.625}^{\circ}$
${0.0109}^{\circ}$

Answer

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Answer

Step 3: Solve for $θ$ : $θ = \arcsin (0.0109) \approx {0.625}^{\circ}$

Steps

Step 1 ：Step 1: Use the formula for bright fringes: $\sin θ = \frac{m λ}{d}$

Step 2 ：Step 2: Substitute given values: $\sin θ = \frac{2 (4.50 \times 10^{- 7} m)}{8.25 \times 10^{- 5} m}$

Step 3 ：Step 3: Solve for $θ$ : $θ = \arcsin (0.0109) \approx {0.625}^{\circ}$