( begin{array}{c}x^{(x-1)^{2}}=2 x+1 x-frac{1}{x}=?end{array} )

Question

( begin{array}{c}x^{(x-1)^{2}}=2 x+1  x-frac{1}{x}=?end{array} )

Accepted Answer

Step:1 ：(x^{(x-1)^{2}}-2x-1=0)Step:2 ：(u=x-1)Step:3 ：(x=u+1)Step:4 ：((u+1)^{u^{2}}-2(u+1)-1=0)Step:5 ：(u=1)Step:6 ：(x=2)Step:7 ：(x-frac{1}{x}=2-frac{1}{2}=frac{3}{2})

Answer

Step: 1 ：(x^{(x-1)^{2}}-2x-1=0)Step: 2 ：(u=x-1)Step: 3 ：(x=u+1)Step: 4 ：((u+1)^{u^{2}}-2(u+1)-1=0)Step: 5 ：(u=1)Step: 6 ：(x=2)Step: 7 ：(x-frac{1}{x}=2-frac{1}{2}=frac{3}{2})

\( \begin{array}{c}x^{(x-1)^{2}}=2 x+1 \\ x-\frac{1}{x}=?\end{array} \)

Answer

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