Use the appropriate compound interest formula to find the amount that will be in each account, given the stated conditions.
$\$ 39,000$ invested at $2 \%$ annual interest for 7 years compounded (a) annually; (b) semiannually
(a) If the interest is compounded annually, there will be $\$ 44798.74$ in the account after 7 years.
(Do not round until the final answer. Then round to the nearest cent as needed.)
(b) If the interest is compounded semiannually, there will be $\$ \square$ in the account after 7 years.
(Do not round until the final answer. Then round to the nearest cent as needed.)

Step 1 ：Recall the formula for compound interest, which is \(A=P\left(1+\frac{r}{n}\right)^{nt}\), where \(A\) is the end balance, \(P\) is the principal, \(r\) is the interest rate, \(t\) is the number of years, and \(n\) is the number of times the interest is compounded in a year.

Step 2 ：Substitute the given values into the formula. The principal \(P\) is \$39,000, the interest rate \(r\) is 2\%, or 0.02, the number of years \(t\) is 7, and the number of times the interest is compounded in a year \(n\) is 2 (since it's compounded semiannually). So we have \(A=39000\left(1+\frac{0.02}{2}\right)^{2 \cdot 7}\).

Step 3 ：Simplify the expression inside the parentheses to get \(A=39000\left(1+0.01\right)^{14}\).

Step 4 ：Calculate the power to get \(A=39000\cdot 1.01^{14}\).

Step 5 ：Calculate the multiplication to get \(A=44798.74\).

Step 6 ：Round to the nearest cent to get \(\boxed{\$44798.74}\).