A vector points 1280 units along the x-axis, and -847 units along the $y$-axis.
Find the magnitude of the vector.
Answer
Final Answer: The magnitude of the vector is \(\boxed{1534.86}\) units.
Step 1 ：We are given a vector that points 1280 units along the x-axis, and -847 units along the y-axis.
Step 2 ：We are asked to find the magnitude of the vector.
Step 3 ：The magnitude of a vector is given by the formula: \(\sqrt{x^2 + y^2}\), where x and y are the components of the vector along the x-axis and y-axis respectively.
Step 4 ：In this case, x = 1280 and y = -847.
Step 5 ：Substituting these values into the formula, we get: \(\sqrt{1280^2 + (-847)^2}\)
Step 6 ：Solving this expression, we find that the magnitude of the vector is approximately 1534.86 units.
Step 7 ：Final Answer: The magnitude of the vector is \(\boxed{1534.86}\) units.
