The point $\mathrm{P}(-7,-2)$ lies on the terminal arm of an angle $\theta$ in standard position.
Determine the measure of $\theta$. Round your answer to 4 decimal places. Use $\pi$ $=3.14159$ if needed.

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Answer

Round the answer to 4 decimal places: $\boxed{3.4199}$

Steps

Step 1 ：Given point P(-7, -2) lies on the terminal arm of an angle $\theta$ in standard position.

Step 2 ：Find the tangent of the angle $\theta$: $\tan(\theta) = \frac{y}{x} = \frac{-2}{-7}$

Step 3 ：Use the arctangent function to find the angle $\theta$: $\theta = \arctan(\frac{-2}{-7})$

Step 4 ：Since point P is in the third quadrant, add $\pi$ to the angle to get the angle in standard position: $\theta_{standard} = \theta + \pi$

Step 5 ：Round the answer to 4 decimal places: $\boxed{3.4199}$