6 Two boys, Shawn and Curtis, went far a walk. Shawn began walking 20 seconds earlier than Curtis.
- Shawn walked at a speed of 5 feet per second.
- Curtis walked at a speed of 6 feet per second.
For how many seconds had Shawn been walking at the moment when the two boys had walked exactly the same distance?

Answer

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Answer

Solve for t: t=\(\frac{120}{1}\)

Steps

Step 1 ：Let s be the distance both Shawn and Curtis walked. Let t be the time Shawn walked for. Then, s=5t for Shawn and s=6(t-20) for Curtis.

Step 2 ：Set the two equations equal to each other: 5t=6(t-20)

Step 3 ：Solve for t: t=\(\frac{120}{1}\)