\( y^{\prime \prime}-y=0 \)
Answer
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Answer
\(y(x) = c_1 \mathrm{e}^x + c_2 \mathrm{e}^{-x}\)
Steps
Step 1 ：\(y^{\prime\prime}(x) - y(x) = 0\)
Step 2 ：\(y(x) = c_1 \mathrm{e}^x + c_2 \mathrm{e}^{-x}\)
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