x^{2}-12 x+36=0

Question

x^{2}-12 x+36=0

Accepted Answer

Step:1 ：Given the quadratic equation: (x^2 - 12x + 36 = 0)Step:2 ：Using the quadratic formula: (x = frac{-b pm sqrt{b^2 - 4ac}}{2a})Step:3 ：Substitute the values: (a = 1), (b = -12), and (c = 36)Step:4 ：Calculate the discriminant: (Delta = b^2 - 4ac = (-12)^2 - 4(1)(36) = 144 - 144 = 0)Step:5 ：Since the discriminant is 0, there is only one solution: (x = frac{-b + sqrt{Delta}}{2a} = frac{12 + sqrt{0}}{2(1)} = frac{12}{2} = 6)Step:6 ：(boxed{x = 6})

Answer

Step: 1 ：Given the quadratic equation: (x^2 - 12x + 36 = 0)Step: 2 ：Using the quadratic formula: (x = frac{-b pm sqrt{b^2 - 4ac}}{2a})Step: 3 ：Substitute the values: (a = 1), (b = -12), and (c = 36)Step: 4 ：Calculate the discriminant: (Delta = b^2 - 4ac = (-12)^2 - 4(1)(36) = 144 - 144 = 0)Step: 5 ：Since the discriminant is 0, there is only one solution: (x = frac{-b + sqrt{Delta}}{2a} = frac{12 + sqrt{0}}{2(1)} = frac{12}{2} = 6)Step: 6 ：(boxed{x = 6})

$x^{2}-12 x+36=0$

Answer

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