Given circle $E$ with diameter $\overset{―}{C D}$ and radius $\overset{―}{E A} \cdot \overset{―}{A B}$ is tangent to $E$ at $A$ . If $A C = 28$ and $E A = 17$ , solve for $E C$ . Round your answer to the nearest tenth if necessary. If the answer cannot be determined, click "Cannot be determined."
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Calculate $E C$ : $E C = \sqrt{28^{2} - 17^{2}} \approx 21.5$

Steps

Step 1 ： $△ A E C$ is a right triangle, as $A C$ is tangent to circle $E$ at $A$ .

Step 2 ：Apply Pythagorean theorem: $A C^{2} = A E^{2} + E C^{2}$

Step 3 ：Solve for $E C$ : $E C = \sqrt{A C^{2} - A E^{2}}$

Step 4 ：Calculate $E C$ : $E C = \sqrt{28^{2} - 17^{2}} \approx 21.5$