Problem

$y = {(x^{2} - 4 x + 1)}^{5}$

Answer

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Answer

$y^{″} = 20 (x^{2} - 4 x + 1)^{3} (2 x - 4)^{2} + 40 (x^{2} - 4 x + 1)^{4}$

Steps

Step 1 ： $y = (x^{2} - 4 x + 1)^{5}$

Step 2 ： $y^{'} = 5 (x^{2} - 4 x + 1)^{4} (2 x - 4)$

Step 3 ： $y^{″} = 20 (x^{2} - 4 x + 1)^{3} (2 x - 4)^{2} + 40 (x^{2} - 4 x + 1)^{4}$

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