Find an equation of the line that goes through the points $(-5,48)$ and $(2,-8)$. Write your answer in the form $y=m x+b$.
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Step 1 ：Given two points $(-5,48)$ and $(2,-8)$, we need to find the equation of the line that passes through these points in the form $y=mx+b$.

Step 2 ：First, we calculate the slope (m) of the line using the formula $m = \frac{y_2 - y_1}{x_2 - x_1}$, where $(x_1, y_1)$ and $(x_2, y_2)$ are the coordinates of the two points.

Step 3 ：Substituting the given points into the formula, we get $m = \frac{-8 - 48}{2 - (-5)} = -8.0$.

Step 4 ：Next, we use the point-slope form of the equation of a line, $y - y_1 = m(x - x_1)$, to find the y-intercept (b).

Step 5 ：Substituting the slope and one of the points into the equation, we get $y - 48 = -8.0(-5 - x)$.

Step 6 ：Solving this equation for y gives us the slope-intercept form: $y = -8.0x + b$.

Step 7 ：Substituting $x = 0$ into the equation, we find that $b = 8.0$.

Step 8 ：Thus, the equation of the line that goes through the points $(-5,48)$ and $(2,-8)$ is $y=-8x+8$.

Step 9 ：\(\boxed{y=-8x+8}\) is the final answer.