The given table indicates the transactions for one teller for one day.
Find the probability that a customer did not withdraw money, given that the customer did not cash a check.
\begin{tabular}{|c|c|c|c|}
\hline Transaction & $\begin{array}{c}\text { Cash } \\
\text { Check }\end{array}$ & No Check & Total \\
\hline $\begin{array}{c}\text { Make } \\
\text { Deposit }\end{array}$ & 25 & 11 & 36 \\
\hline Withdraw & 28 & 12 & 40 \\
\hline Other & 23 & 15 & 38 \\
\hline Total & 76 & 38 & 114 \\
\hline
\end{tabular}
$P(E \mid F)=\square$ (Type an integer or a simplified fraction.)

Step 1 ：The given table indicates the transactions for one teller for one day. We are asked to find the probability that a customer did not withdraw money, given that the customer did not cash a check. This is a conditional probability problem. We can use the formula for conditional probability, which is \(P(E|F) = \frac{P(E \cap F)}{P(F)}\). Here, event E is the event that a customer did not withdraw money, and event F is the event that the customer did not cash a check.

Step 2 ：From the table, we can see that the total number of customers who did not cash a check is 38. This is \(P(F)\).

Step 3 ：The number of customers who did not withdraw money and did not cash a check is the sum of the number of customers who made a deposit and did not cash a check and the number of customers who did other transactions and did not cash a check. This is \(P(E \cap F)\).

Step 4 ：We can calculate these values and substitute them into the formula to find the answer. The total number of customers who did not cash a check is 38, and the number of customers who did not withdraw money and did not cash a check is 26.

Step 5 ：Substituting these values into the formula, we get \(P(E|F) = \frac{26}{38} = 0.6842105263157895\).

Step 6 ：Final Answer: The probability that a customer did not withdraw money, given that the customer did not cash a check is approximately \(\boxed{0.684}\).