This problem involves empirical probability. The table shows the breakdown of 90 thousand single parents on active duty in the U.S. military in a certain year. All numbers are in thousands and rounded to the nearest thousand. Use the data in the table to find the probability that a randomly selected single parent in the U.S. military is in the Army.
\begin{tabular}{|l|c|c|c|c|c|}
\hline & Army & Navy & $\begin{array}{c}\text { Marine } \\
\text { Corps }\end{array}$ & $\begin{array}{c}\text { Air } \\
\text { Force }\end{array}$ & Total \\
\hline Male & 23 & 24 & 6 & 14 & 67 \\
\hline Female & 9 & 7. & 1 & 6 & 23 \\
\hline Total & 32 & 31 & 7 & 20 & 90 \\
\hline
\end{tabular}
The probability that a randomly selected single parent in the U.S. military is in the Army is

Step 1 ：This problem involves empirical probability. The table shows the breakdown of 90 thousand single parents on active duty in the U.S. military in a certain year. All numbers are in thousands and rounded to the nearest thousand. Use the data in the table to find the probability that a randomly selected single parent in the U.S. military is in the Army.

Step 2 ：The probability of an event is calculated by dividing the number of ways the event can occur by the total number of outcomes. In this case, the event is a single parent in the U.S. military being in the Army. The number of ways this event can occur is the total number of single parents in the Army, which is 32 thousand. The total number of outcomes is the total number of single parents in the U.S. military, which is 90 thousand.

Step 3 ：Therefore, the probability can be calculated by dividing 32 by 90.

Step 4 ：\(\frac{32}{90} = 0.35555555555555557\)

Step 5 ：Final Answer: The probability that a randomly selected single parent in the U.S. military is in the Army is approximately \(\boxed{0.356}\).