Find the probability that when a couple has three children, at least one of them is a girl. (Assume that boys and girls are equally likely.)

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Step:1 ：Given that the probability of having a boy or a girl is (frac{1}{2}).Step:2 ：The only way to not have at least one girl is if all three children are boys.Step:3 ：The probability of having three boys is (left(frac{1}{2}right) * left(frac{1}{2}right) * left(frac{1}{2}right) = frac{1}{8}).Step:4 ：Therefore, the probability of having at least one girl is 1 - the probability of having all boys.Step:5 ：Substituting the values, we get (1 - frac{1}{8} = frac{7}{8}) or 0.875.Step:6 ：Final Answer: The probability that when a couple has three children, at least one of them is a girl is (boxed{0.875}).

Answer

Step: 1 ：Given that the probability of having a boy or a girl is (frac{1}{2}).Step: 2 ：The only way to not have at least one girl is if all three children are boys.Step: 3 ：The probability of having three boys is (left(frac{1}{2}right) * left(frac{1}{2}right) * left(frac{1}{2}right) = frac{1}{8}).Step: 4 ：Therefore, the probability of having at least one girl is 1 - the probability of having all boys.Step: 5 ：Substituting the values, we get (1 - frac{1}{8} = frac{7}{8}) or 0.875.Step: 6 ：Final Answer: The probability that when a couple has three children, at least one of them is a girl is (boxed{0.875}).

Find the probability that when a couple has three children, at least one of them is a girl. (Assume that boys and girls are equally likely.)

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