Problem

Find the inverse of the matrix
\[
A=\left(\begin{array}{lll}
0 & 1 & 1 \\
1 & 1 & 1 \\
1 & 1 & 2
\end{array}\right)
\]

Answer

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Answer

\(\boxed{A^{-1} = \left(\begin{array}{lll} -1 & 1 & 0 \\ 1 & 1 & -1 \\ 0 & -1 & 1 \end{array}\right)}\)

Steps

Step 1 :Find the determinant of the matrix \(A\): \[\text{det}(A) = -1\]

Step 2 :Since the determinant is non-zero, the inverse of \(A\) exists.

Step 3 :Find the adjugate of the matrix \(A\): \[\text{adj}(A) = \left(\begin{array}{lll} 1 & -1 & 0 \\ -1 & -1 & 1 \\ 0 & 1 & -1 \end{array}\right)\]

Step 4 :Calculate the inverse of \(A\) using the formula: \[A^{-1} = \frac{1}{\text{det}(A)} \text{adj}(A)\]

Step 5 :\(\boxed{A^{-1} = \left(\begin{array}{lll} -1 & 1 & 0 \\ 1 & 1 & -1 \\ 0 & -1 & 1 \end{array}\right)}\)

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