Evaluate the following integral.
\[
\int_{0}^{5} \frac{4 x-3}{x+1} d x
\]
\[
\int_{0}^{5} \frac{4 x-3}{x+1} d x=\mid \text { (Type an exact answer) }
\]

Answer

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Answer

\(\boxed{20 - 7 \log(6)}\) is the final answer.

Steps

Step 1 ：The integral can be simplified by dividing the numerator by the denominator, which results in a polynomial. The integral of a polynomial can be easily calculated.

Step 2 ：The integral of the function from 0 to 5 is \(20 - 7 \log(6)\).

Step 3 ：\(\boxed{20 - 7 \log(6)}\) is the final answer.

Evaluate the following integral.\[\int_{0}^{5} \frac{4 x-3}{x+1} d x\]\[\int_{0}^{5} \frac{4 x-3}{x+1} d x=\mid \text { (Type an exact answer) }\]

Answer

Popular Problems

Evaluate the following integral.
\[
\int_{0}^{5} \frac{4 x-3}{x+1} d x
\]
\[
\int_{0}^{5} \frac{4 x-3}{x+1} d x=\mid \text { (Type an exact answer) }
\]