Problem

Examples:
Find the Fourier series of the function \( f(x)=x+\pi \) if \( -\pi< x< \pi \) and \( f(x+2 \pi)=f(x) \).
Solution:

Answer

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Answer

Step 9: Fourier series = \( f(x) = 1 + \sum_{n=1}^{\infty} \frac{2}{n} \sin(nx) \)

Steps

Step 1 :Step 1: Calculate Fourier coefficients a_0, a_n and b_n

Step 2 :Step 2: a_0 = \( \frac{1}{\pi} \int_{-\pi}^{\pi} (x + \pi) \, dx \)

Step 3 :Step 3: a_0 = \( \frac{1}{\pi} \times \pi = 1 \)

Step 4 :Step 4: a_n = \( \frac{1}{\pi} \int_{-\pi}^{\pi} (x + \pi) \cos(nx) \, dx \)

Step 5 :Step 5: a_n = 0

Step 6 :Step 6: b_n = \( \frac{1}{\pi} \int_{-\pi}^{\pi} (x + \pi) \sin(nx) \, dx \)

Step 7 :Step 7: b_n = \( \frac{2}{n} \)

Step 8 :Step 8: Fourier series = \( f(x) = a_0 + \sum_{n=1}^{\infty} a_n \cos(nx) + b_n \sin(nx) \)

Step 9 :Step 9: Fourier series = \( f(x) = 1 + \sum_{n=1}^{\infty} \frac{2}{n} \sin(nx) \)

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