A chemical reaction produces 0.153 moles of nitrogen gas. What volume in liters will this gas occupy at STP?
\(V = 3.4157 \text{ L}\)
Step 1 :\(n = 0.153 \text{ moles}\)
Step 2 :\(V = \frac{nRT}{P} = \frac{0.153 \times 0.0821 \times 273}{1} \text{ L}\)
Step 3 :\(V = 3.4157 \text{ L}\)