Find the average rate of change of $f(x)=2 x^{3}$ on the interval $[5,9]$. Simplify your answer. Do not round.
Average Rate of Change $=$

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Final Answer: The average rate of change of $f(x)=2 x^{3}$ on the interval [5,9] is $\boxed{302}$

Steps

Step 1 ：Given the function $f(x) = 2x^3$ and the interval [5, 9].

Step 2 ：The average rate of change of a function on an interval [a, b] is given by the formula: \[\frac{f(b) - f(a)}{b - a}\]

Step 3 ：Substitute a = 5 and b = 9 into the formula: \[\frac{f(9) - f(5)}{9 - 5}\]

Step 4 ：Calculate $f(9)$ and $f(5)$ by substituting 9 and 5 into the function $f(x) = 2x^3$ respectively.

Step 5 ：Simplify the expression to get the average rate of change.

Step 6 ：Final Answer: The average rate of change of $f(x)=2 x^{3}$ on the interval [5,9] is $\boxed{302}$