$(x+1)(3 x-1)$
So, the expanded form of the expression $(x+1)(3 x-1)$ is \(\boxed{3x^2 + 2x - 1}\).
Step 1 :Let's solve the expression $(x+1)(3 x-1)$.
Step 2 :We can use the distributive property to multiply each term in the first binomial by each term in the second binomial.
Step 3 :First, multiply the first terms: $x * 3x = 3x^2$.
Step 4 :Second, multiply the outer terms: $x * -1 = -x$.
Step 5 :Third, multiply the inner terms: $1 * 3x = 3x$.
Step 6 :Finally, multiply the last terms: $1 * -1 = -1$.
Step 7 :Combine like terms: $3x^2 - x + 3x - 1 = 3x^2 + 2x - 1$.
Step 8 :So, the expanded form of the expression $(x+1)(3 x-1)$ is \(\boxed{3x^2 + 2x - 1}\).