Choose the right coefficients to balance
\[
\mathrm{AlBr} 3+\mathrm{K} 2 \mathrm{SO} 4-\cdots> \mathrm{KBr}+\mathrm{Al} 2(\mathrm{SO} 4) 3
\]
$1,3,6,1$
$3,2,6,1$
$2,3,6,1$
$3,2,6,1$

Step 1 ：The equation is: \(\mathrm{AlBr}_3 + \mathrm{K}_2\mathrm{SO}_4 \rightarrow \mathrm{KBr} + \mathrm{Al}_2(\mathrm{SO}_4)_3\)

Step 2 ：Start by balancing the Al and Br atoms. There are 2 Al atoms on the right side of the equation, so put a coefficient of 2 in front of \(\mathrm{AlBr}_3\) on the left side. This gives 6 Br atoms on the left side, so put a coefficient of 6 in front of \(\mathrm{KBr}\) on the right side.

Step 3 ：Next, balance the K and \(\mathrm{SO}_4\) atoms. There are 6 K atoms on the right side, so put a coefficient of 3 in front of \(\mathrm{K}_2\mathrm{SO}_4\) on the left side. This gives 3 \(\mathrm{SO}_4\) groups on the left side, which matches the number on the right side.

Step 4 ：So, the balanced equation is: \(2\mathrm{AlBr}_3 + 3\mathrm{K}_2\mathrm{SO}_4 \rightarrow 6\mathrm{KBr} + \mathrm{Al}_2(\mathrm{SO}_4)_3\)

Step 5 ：The correct coefficients to balance the equation are \(\boxed{2, 3, 6, 1}\).