Problem

Question 32 (1 point)
Given $\cos \theta=-\frac{\sqrt{3}}{2}$, determine all possible values of $\theta$, if $0 \leq \theta \leq 360^{\circ}$.
$\theta=150^{\circ}, \theta=210^{\circ}$
$\theta=120^{\circ}, \theta=240^{\circ}$
$\theta=240^{\circ}, \theta=300^{\circ}$
$\theta=330^{\circ}, \theta=210^{\circ}$

Answer

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Answer

The possible values of \(\theta\) are \(\boxed{150^{\circ}}\) and \(\boxed{210^{\circ}}\).

Steps

Step 1 :Given \(\cos \theta=-\frac{\sqrt{3}}{2}\), determine all possible values of \(\theta\), if \(0 \leq \theta \leq 360^{\circ}\).

Step 2 :The possible values of \(\theta\) are \(\boxed{150^{\circ}}\) and \(\boxed{210^{\circ}}\).

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