The table shows the probabilities of the number of DVDs in a house based on information gathered through a survey
\begin{tabular}{r|rrrrr}
Number of DVDs & 0 & 1 & 2 & 3 & 4 or more \\
\hline Probability & 0.05 & 0.24 & 0.33 & 0.21 & 0.17
\end{tabular}
Find the probability of a house having fewer than 2 DVDs.
Answer
Final Answer: The probability of a house having fewer than 2 DVDs is \(\boxed{0.29}\).
Step 1 ：The table shows the probabilities of the number of DVDs in a house based on information gathered through a survey. The probabilities are as follows: \(P(0) = 0.05\), \(P(1) = 0.24\), \(P(2) = 0.33\), \(P(3) = 0.21\), and \(P(4 \text{ or more}) = 0.17\).
Step 2 ：We are asked to find the probability of a house having fewer than 2 DVDs. This means we need to find \(P(0) + P(1)\).
Step 3 ：By adding the probabilities, we get \(P(0) + P(1) = 0.05 + 0.24 = 0.29\).
Step 4 ：Final Answer: The probability of a house having fewer than 2 DVDs is \(\boxed{0.29}\).
