A system of equations was written as an augmented matrix, which was row reduced to:
\[
\left[\begin{array}{cccc}
1 & 0 & 0 & 3 \\
0 & 1 & 0 & -4 \\
0 & 0 & 1 & 0
\end{array}\right]
\]
What is the solution to the original system of equations?
\[
\begin{array}{l}
x= \\
y= \\
z=
\end{array}
\]
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Answer
Final Answer: \[\begin{array}{l}x= \boxed{3} \y= \boxed{-4} \z= \boxed{0}\end{array}\]
Step 1 ：The given matrix is in row echelon form, which means each row represents an equation in the system. The first column represents the coefficient of x, the second column represents the coefficient of y, and the third column represents the coefficient of z. The fourth column represents the constants on the other side of the equation.
Step 2 ：Therefore, the system of equations represented by this matrix is: x = 3, y = -4, z = 0.
Step 3 ：So, the solution to the system of equations is x = 3, y = -4, z = 0.
Step 4 ：Final Answer: \[\begin{array}{l}x= \boxed{3} \y= \boxed{-4} \z= \boxed{0}\end{array}\]
