\[
\begin{array}{l}
f(x)=x-14 \\
g(x)=3 x^{2}-6 x-10
\end{array}
\]

Find: $f(g(x))$

Answer

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Answer

So, the final answer is $\boxed{f(g(x)) = 3x^2 - 6x - 24}$.

Steps

Step 1 ：Given that $f(x) = x - 14$ and $g(x) = 3x^2 - 6x - 10$, we substitute $g(x)$ into $f(x)$ to find $f(g(x))$.

Step 2 ：So, $f(g(x)) = f(3x^2 - 6x - 10)$.

Step 3 ：By substituting $3x^2 - 6x - 10$ into $f(x)$, we get $f(g(x)) = (3x^2 - 6x - 10) - 14$.

Step 4 ：Simplify the expression to get $f(g(x)) = 3x^2 - 6x - 24$.

Step 5 ：So, the final answer is $\boxed{f(g(x)) = 3x^2 - 6x - 24}$.