Let $A = [\begin{array}{ll} 2 & 3 \\ 2 & 6 \end{array}]$ and $B = [\begin{array}{rr} 0 & 4 \\ - 1 & 6 \end{array}]$ . Find $2 A + B$ .
A. $[\begin{array}{ll} 4 & 14 \\ 2 & 24 \end{array}]$
B. $[\begin{array}{rr} 4 & 7 \\ 3 & 12 \end{array}]$
c. $[\begin{array}{ll} 4 & 10 \\ 3 & 18 \end{array}]$
D. $[\begin{array}{ll} 4 & 10 \\ 1 & 12 \end{array}]$

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Answer

$[\begin{array}{ll} 4 & 10 \\ 3 & 18 \end{array}]$ is the final answer.

Steps

Step 1 ：Find $2 A$ by multiplying each element in matrix $A$ by 2: $2 A = 2 * [\begin{array}{ll} 2 & 3 \\ 2 & 6 \end{array}] = [\begin{array}{ll} 4 & 6 \\ 4 & 12 \end{array}]$

Step 2 ：Add $2 A$ to $B$ by adding the corresponding elements in each matrix: $2 A + B = [\begin{array}{ll} 4 & 6 \\ 4 & 12 \end{array}] + [\begin{array}{rr} 0 & 4 \\ - 1 & 6 \end{array}] = [\begin{array}{ll} 4 & 10 \\ 3 & 18 \end{array}]$

Step 3 ： $[\begin{array}{ll} 4 & 10 \\ 3 & 18 \end{array}]$ is the final answer.

Let A=[2326] and B=[04−16]. Find 2A+B.A. [414224]B. [47312]c. [410318]D. [410112]

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