Express each equation in logarithmic form.
(a) $e^{x}=5$ is equivalent to the logarithmic equation:
(b) $e^{7}=x$ is equivalent to the logarithmic equation:
(b) The logarithmic form of \(e^{7}=x\) is \(\boxed{\ln x = 7}\) or \(\boxed{\log_{e}x = 7}\).
Step 1 :Express each equation in logarithmic form.
Step 2 :The general form of an exponential equation is \(b^{y} = x\), where \(b\) is the base, \(y\) is the exponent, and \(x\) is the result. This can be converted into logarithmic form as \(\log_{b}x = y\).
Step 3 :For the first equation, \(e^{x}=5\), the base is \(e\), the exponent is \(x\), and the result is \(5\). So, the logarithmic form would be \(\log_{e}5 = x\).
Step 4 :For the second equation, \(e^{7}=x\), the base is \(e\), the exponent is \(7\), and the result is \(x\). So, the logarithmic form would be \(\log_{e}x = 7\).
Step 5 :Note that \(\log_{e}\) is also represented as \(\ln\).
Step 6 :\(\boxed{\text{Final Answer:}}\)
Step 7 :(a) The logarithmic form of \(e^{x}=5\) is \(\boxed{\ln5 = x}\) or \(\boxed{\log_{e}5 = x}\).
Step 8 :(b) The logarithmic form of \(e^{7}=x\) is \(\boxed{\ln x = 7}\) or \(\boxed{\log_{e}x = 7}\).