Find the sum of the first 44 terms of the following series, to the nearest integer.
\[
10,14,18, \ldots
\]

Step 1 ：We are given an arithmetic series where the first term (a) is 10, the common difference (d) is 4, and the number of terms (n) is 44.

Step 2 ：We can find the sum of the first n terms of an arithmetic series using the formula: \(S_n = \frac{n}{2} \times (a + l)\), where \(S_n\) is the sum of the first n terms, \(n\) is the number of terms, \(a\) is the first term, and \(l\) is the last term.

Step 3 ：We know \(n = 44\) and \(a = 10\), but we don't know \(l\). We can find \(l\) using the formula for the nth term of an arithmetic series: \(l = a + (n - 1) \times d\), where \(d\) is the common difference. In this case, \(d = 4\).

Step 4 ：Substituting the given values into the formula, we find that \(l = 10 + (44 - 1) \times 4 = 182\).

Step 5 ：Now we can substitute \(n = 44\), \(a = 10\), and \(l = 182\) into the formula for \(S_n\) to find the sum of the first 44 terms of the series: \(S_n = \frac{44}{2} \times (10 + 182) = 4224.0\).

Step 6 ：Rounding to the nearest integer, we get \(S_n = 4224\).

Step 7 ：Final Answer: The sum of the first 44 terms of the series, to the nearest integer, is \(\boxed{4224}\).