Find the prime factorization of the number 116.
Order the factors from least to greatest. Remember, 1 is not a prime number.
\[
2 \times[?] \times
\]
Enter the number that belongs in the green box.
Enter
Answer
The prime factorization of 116 is \(2 \times 2 \times 29\). Therefore, the number that belongs in the green box is \(\boxed{2}\).
Step 1 ：Find the prime factorization of the number 116.
Step 2 ：Order the factors from least to greatest. Remember, 1 is not a prime number.
Step 3 ：The prime factorization of a number is the expression of that number as a product of prime numbers. To find the prime factorization of 116, we need to divide it by prime numbers starting from the smallest one (which is 2) until we can't divide it anymore.
Step 4 ：The prime factorization of 116 is \(2 \times 2 \times 29\). Therefore, the number that belongs in the green box is \(\boxed{2}\).
