Question 3 (1 point)
Solve the linear-exponential system of equations by graphing on your own paper. Express your values as decimals rounded to the nearest hundredth, if necessary.
$\begin{array}{l} y = 0.6 x - 4.3 \\ y = (x - 5)^{2} - 1 \end{array}$

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Answer

$The system of equations has no real solutions.$

Steps

Step 1 ：Set the two equations equal to each other: $0.6 x - 4.3 = (x - 5)^{2} - 1$ .

Step 2 ：Solve for x to find the intersection points. The solutions are $x = 5.3 - 0.458257569495584 i$ and $x = 5.3 + 0.458257569495584 i$ .

Step 3 ：Substitute the x-values into either of the original equations to find the corresponding y-values. The solutions are $y = - 1.12 - 0.27495454169735 i$ and $y = - 1.12 + 0.27495454169735 i$ .

Step 4 ：The solutions to the system of equations are complex numbers, which means that the graphs of the two functions do not intersect at any real points.

Step 5 ： $The system of equations has no real solutions.$

Question 3 (1 point)Solve the linear-exponential system of equations by graphing on your own paper. Express your values as decimals rounded to the nearest hundredth, if necessary.y=0.6x−4.3y=(x−5)2−1

Answer

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Question 3 (1 point)
Solve the linear-exponential system of equations by graphing on your own paper. Express your values as decimals rounded to the nearest hundredth, if necessary.
$\begin{array}{l} y = 0.6 x - 4.3 \\ y = (x - 5)^{2} - 1 \end{array}$