For $4 y+2 x=-8$ determine the value of $y$ when $x=0$, and the value of $x$ when $y=$ 0. Then graph the line using the identified intercepts.

Step 1 ：Given the equation \(4y + 2x = -8\)

Step 2 ：To find the y-intercept, we set \(x=0\) and solve for \(y\)

Step 3 ：Substituting \(x=0\) into the equation gives \(4y + 2(0) = -8\), which simplifies to \(4y = -8\)

Step 4 ：Solving for \(y\) gives \(y = -2\)

Step 5 ：To find the x-intercept, we set \(y=0\) and solve for \(x\)

Step 6 ：Substituting \(y=0\) into the equation gives \(4(0) + 2x = -8\), which simplifies to \(2x = -8\)

Step 7 ：Solving for \(x\) gives \(x = -4\)

Step 8 ：The line represented by the equation \(4y + 2x = -8\) passes through the y-intercept \(y=-2\) and the x-intercept \(x=-4\)

Step 9 ：\(\boxed{\text{Final Answer: The y-intercept is } y=-2 \text{ and the x-intercept is } x=-4}\)