Problem

\( \frac{x^{2}+10 x+21}{x^{2}-9} \)

Answer

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Answer

\( \frac{(x+3)(x+7)}{(x-3)(x+3)} = \frac{x+7}{x-3} \)

Steps

Step 1 ：\( \frac{x^{2}+10x+21}{x^{2}-9} = \frac{(x+3)(x+7)}{(x-3)(x+3)} \)

Step 2 ：\( \frac{(x+3)(x+7)}{(x-3)(x+3)} = \frac{x+7}{x-3} \)

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