int_{0}^{4} 10 x d x=

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Accepted Answer

Step:1 ：The question is asking for the definite integral of the function 10x from 0 to 4. The integral of 10x is 5x^2. To find the definite integral, we need to evaluate the function at the upper limit and subtract the function evaluated at the lower limit.Step:2 ：Substitute x = 4 into the function 5x^2 to get 5*(4)^2 = 80.Step:3 ：Substitute x = 0 into the function 5x^2 to get 5*(0)^2 = 0.Step:4 ：Subtract the value of the function at the lower limit from the value at the upper limit to get 80 - 0 = 80.Step:5 ：Final Answer: (boxed{80})

Answer

Step: 1 ：The question is asking for the definite integral of the function 10x from 0 to 4. The integral of 10x is 5x^2. To find the definite integral, we need to evaluate the function at the upper limit and subtract the function evaluated at the lower limit.Step: 2 ：Substitute x = 4 into the function 5x^2 to get 5*(4)^2 = 80.Step: 3 ：Substitute x = 0 into the function 5x^2 to get 5*(0)^2 = 0.Step: 4 ：Subtract the value of the function at the lower limit from the value at the upper limit to get 80 - 0 = 80.Step: 5 ：Final Answer: (boxed{80})

$\int_{0}^{4} 10 x d x=$

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