Use the given conditions to write an equation for the line in point-slope form and in slope-intercept form.
Passing through $(-3,-4)$ and parallel to the line whose equation is $y=-5x+2$

Step 1 ：Find the slope of the given line. The slope of a line in the form $y=mx+b$ is $m$. So, the slope of the given line is $-5$. Since parallel lines have the same slope, the slope of the line we are trying to find is also $-5$.

Step 2 ：Use the point-slope form of a line, which is $y-y_1=m(x-x_1)$, where $(x_1,y_1)$ is a point on the line and $m$ is the slope. Substitute $-3$ for $x_1$, $-4$ for $y_1$, and $-5$ for $m$.

Step 3 ：Convert the point-slope form to the slope-intercept form, which is $y=mx+b$. Do this by solving the point-slope equation for $y$.

Step 4 ：The point-slope form of the line is $y+4=-5(x+3)$ and the slope-intercept form of the line is $y=-5x-19$.

Step 5 ：$\boxed{{\displaystyle \text{The point-slope form of the line is }y+4=-5(x+3)\text{ and the slope-intercept form of the line is }y=-5x-19}}$