Use the given conditions to write an equation for the line in point-slope form and in slope-intercept form.
Passing through $(-3,-4)$ and parallel to the line whose equation is $y=-5 x+2$

Step 1 ：Find the slope of the given line. The slope of a line in the form \(y = mx + b\) is \(m\). So, the slope of the given line is \(-5\). Since parallel lines have the same slope, the slope of the line we are trying to find is also \(-5\).

Step 2 ：Use the point-slope form of a line, which is \(y - y_1 = m(x - x_1)\), where \((x_1, y_1)\) is a point on the line and \(m\) is the slope. Substitute \(-3\) for \(x_1\), \(-4\) for \(y_1\), and \(-5\) for \(m\).

Step 3 ：Convert the point-slope form to the slope-intercept form, which is \(y = mx + b\). Do this by solving the point-slope equation for \(y\).

Step 4 ：The point-slope form of the line is \(y + 4 = -5(x + 3)\) and the slope-intercept form of the line is \(y = -5x - 19\).

Step 5 ：\(\boxed{\text{The point-slope form of the line is } y + 4 = -5(x + 3) \text{ and the slope-intercept form of the line is } y = -5x - 19}\)