Problem

$2 x^{2}+3 x-2=0$

Answer

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Answer

\boxed{\text{Final Answer: } x = 0.5 \text{ and } x = -2.0}

Steps

Step 1 :Given the quadratic equation \(2x^2 + 3x - 2 = 0\), we can use the quadratic formula: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), where \(a = 2\), \(b = 3\), and \(c = -2\)

Step 2 :Calculate the discriminant: \(\Delta = b^2 - 4ac = 25\)

Step 3 :Find the two possible values for x: \(x_1 = \frac{-3 + \sqrt{25}}{4} = 0.5\) and \(x_2 = \frac{-3 - \sqrt{25}}{4} = -2.0\)

Step 4 :\boxed{\text{Final Answer: } x = 0.5 \text{ and } x = -2.0}

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