Problem

Find the four second-order partial derivatives for f(x,y)=8x8y7+6x5y6
fxx=
fyy=
fxy=
fyx=

Answer

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Answer

fyx=4x4y5(112x3y+45)

Steps

Step 1 :Given the function f(x,y)=8x8y7+6x5y6, we are asked to find the four second-order partial derivatives.

Step 2 :The second-order partial derivatives are the derivatives of the first-order partial derivatives. The first-order partial derivatives are found by differentiating the function with respect to one variable while holding the other variable constant. The second-order partial derivatives are found by differentiating the first-order partial derivatives with respect to the other variable.

Step 3 :The four second-order partial derivatives are: fxx, the second derivative of f with respect to x; fyy, the second derivative of f with respect to y; fxy, the derivative of f with respect to x and then y; and fyx, the derivative of f with respect to y and then x.

Step 4 :By applying the rules of differentiation, we find that fxx=8x3y6(56x3y+15), fyy=12x5y4(28x3y+15), fxy=4x4y5(112x3y+45), and fyx=4x4y5(112x3y+45).

Step 5 :fxx=8x3y6(56x3y+15)

Step 6 :fyy=12x5y4(28x3y+15)

Step 7 :fxy=4x4y5(112x3y+45)

Step 8 :fyx=4x4y5(112x3y+45)

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